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The secret that "X" doesn't want you to know!

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OperatorStandingBy View Drop Down
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    Posted: 24 Feb 2017 at 5:48pm
I just LOVE (sarcasm) those radio commercials which supposedly reveal "secrets" to being or doing certain things that some entity (or entities) doesn't/don't want you to know about.
 
Well now that it's been blasted over the airwaves, it's no longer a secret, now is it?
 
Speaking of which, these also happen to be the same ads where the phone number to call is repeated ad nauseum.   It's like nails on a chalkboard.
 
Sorry, don't care to look like a slimmed-down, younger-looking house flipper with a head full of hair, thanks.............
"I believe......if Cialis really works, shouldn't that couple be in the same bathtub?" - Bill Engvall
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aka ron View Drop Down
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Post Options Post Options   Thanks (0) Thanks(0)   Quote aka ron Quote  Post ReplyReply Direct Link To This Post Posted: 24 Feb 2017 at 8:19pm

Ancient Chinese Secret?

Secret Deodorant?
 
Donna's double dumbass identity club?
 
X=
 

This theorem bridges the antiderivative concept with the area problem. Indeed, let f (x) be a function defined and continuous on [a, b]. Consider the function

F(x) = $\displaystyle \int_{a}^{x}$f (t)dt
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DirtyD79 View Drop Down
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Post Options Post Options   Thanks (0) Thanks(0)   Quote DirtyD79 Quote  Post ReplyReply Direct Link To This Post Posted: 01 Mar 2017 at 8:44am
The ones that really annoy me are the ones where they start off with "This man predicts a major economic collapse or event that will change the way you live, work, eat, sleep, masturbate, or whatever." They always turn out to be Ron Paul and the Randroids hawkin' gold.
Mind on My Money, Money on My Beer
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Post Options Post Options   Thanks (0) Thanks(0)   Quote Dr. Dan Quote  Post ReplyReply Direct Link To This Post Posted: 15 Jun 2018 at 12:15am
Originally posted by aka ron aka ron wrote:

Ancient Chinese Secret?


Secret Deodorant?

 

Donna's double dumbass identity club?

 

X=

 


This theorem bridges the antiderivative concept with the area problem. Indeed, let f (x) be a function defined and continuous on [a, b]. Consider the function <!-- MATH   begindisplaymath Fx = int_a^x ft dt enddisplaymath   -->


F(x) = $\displaystyle \int_{a}^{x}$f (t)dt

So this is the formula for how Deal Dash works! Thank you!

Forgive me for posting to a thread that's more than twelve months old.
LiMu Emu: the NEXT red meat!
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